- #1

late347

- 301

- 15

## Homework Statement

the velocity of a harmonic wave in a strung-wire is 1550m/s

and the wave's frequency is 740Hz

there are two oscillators (?) in the wave called A and B such that B is 2m further ahead of A in the direction of the wave's travela) calculate the phase difference between A and B

b) If A at the time of t=0, is at its equilibrium position (?), then at what time (any one moment in time), will B be at its own equilibrium position?

## Homework Equations

v=fλ wave equation

ΔΘ=k*Δx phase difference

##k= (2\pi)/\lambda##

possibly useful

##y(x, t) = \hat{y}sin[\omega *t -kx]##

## The Attempt at a Solution

a) the problem is easily calculated by using wave equation to get wavelength

then find wavenumber k

wavelength = v/f

=2,0946m

k= 2,9997 radian/m

ΔΘ= 2,9997 radian/m * 2m = 5,9994 radians

b) honestly I was a little bit stuck at even understanding the question here. It says that A will be somewhere at an equilibrium position. I have a vague memory that in this particular case it means that the y value = 0 at that particular time. Because if we use the function y(x,t), it measures the y.

If you had a spring and a weight system (without friction) and the weight would go back and forth with the spring, then magnitude of springn Force increases directly proportional to the displacement from equilibrium position (?)

1.) I'm not really sure how or if that function formula is supposed to be used though.

the function y(x,t) = something

2.) and furthermore can the function be used to solve the problem, because we don't t´know the value of ##\hat{y}## ?

any tips to the B part would be welcome