Overall Thermal Conductivity of Three different layers

Click For Summary
SUMMARY

The discussion focuses on calculating the overall thermal conductivity of a composite material consisting of three distinct layers with varying thermal conductivities and thicknesses. The thermal conductivities are k1 = 1 W/m-K for layer 1 (thickness t1 = 0.004 m), k2 = 148 W/m-K for layer 2 (thickness t2 = 0.0003 m), and k3 = 0.23 W/m-K for layer 3 (thickness t3 = 0.004 m). To determine the overall thermal conductivity, one must calculate the thermal resistance of each layer, sum these resistances, and then recalculate the compound conductivity based on the total resistance.

PREREQUISITES
  • Understanding of thermal conductivity and its units (W/m-K)
  • Knowledge of thermal resistance calculations
  • Familiarity with composite material properties
  • Basic mathematical skills for summing resistances and calculating overall conductivity
NEXT STEPS
  • Research the formula for calculating thermal resistance: R = t/k
  • Learn how to derive overall thermal conductivity from multiple layers
  • Explore applications of composite materials in thermal management
  • Investigate software tools for thermal analysis, such as ANSYS or COMSOL Multiphysics
USEFUL FOR

Engineers, materials scientists, and students involved in thermal analysis and composite material design will benefit from this discussion.

Izazo
Messages
7
Reaction score
0
TL;DR
How to calculate the overall conductivity of three layers bonded with each other having different thermal conductivities?
Overall thermal conductivity?
for example, there are 3 layers made of different materials, having different thermal conductivities bonded with each other;
conductivity of layer 1= k_1 = 1 W/m-K
thickness of layer 1= t_1 = 0.004 m

conductivity of layer 2= k_2 = 148 W/m-K
thickness of layer 2= t_2 = 0.0003 m

conductivity of layer 3= k_3 = 0.23 W/m-K
thickness of layer 3= t_3 = 0.004 m
 
Engineering news on Phys.org
You should calculate thermal resistance of each layer, sum up resistances end recalculate compound conductivity from the sum.
 
  • Like
Likes   Reactions: MRFMengineer

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K