Oxidation Number to balance a redox reaction

  • Thread starter agnibho
  • Start date
  • #1
46
0

Homework Statement


Balance Cl2+NaOH -> NaCl + NaClO3 + H2O
 

Answers and Replies

  • #2
chemisttree
Science Advisor
Homework Helper
Gold Member
3,512
545
Start by determining the oxidation numbers of all species.
 
  • #3
46
0
Cl02 + Na+1O-2H+1 -> Na+1Cl + Na+1Cl-1O3-2 + H2+1O-2

To equalize the Oxidation Numbers of Cl and Na, 3 atoms of Cl and 6 atoms of Na are required. Thus,
3Cl2 + 6NaOH -> 5NaCl + NaClO3 + xH2O
By inspection x = 3
∴ 3Cl2 + 6NaOH -> 5NaCl + NaClO3 + 3H2O

I think this is correct, but if I have done something wrong please tell me so, as I'm new to this topic.
Thanks in advance.
 
  • #4
Borek
Mentor
28,600
3,078
No idea what you mean by "equalize the ON", specially in the context of sodium - ON for sodium doesn't change, and Na+ is only a spectator.

You have Cl(0) on the left and Cl(+1) and Cl(-1) on the right. This is disproportionation - teh same element becomes both oxidized and reduced at the same time. Can you tell how many atoms of Cl get oxidized if 1 atom gets reduced?
 

Related Threads on Oxidation Number to balance a redox reaction

Replies
5
Views
1K
Replies
6
Views
1K
Replies
11
Views
7K
  • Last Post
Replies
5
Views
2K
  • Last Post
Replies
7
Views
3K
  • Last Post
Replies
1
Views
4K
  • Last Post
Replies
3
Views
831
  • Last Post
Replies
1
Views
3K
  • Last Post
Replies
1
Views
3K
  • Last Post
Replies
3
Views
897
Top