Oxidation Number to balance a redox reaction

[agnibho]

Homework Statement

Balance Cl₂+NaOH -> NaCl + NaClO₃ + H₂O

 

[chemisttree]

Start by determining the oxidation numbers of all species.

 

[agnibho]

Cl⁰₂ + Na⁺¹O^-2H⁺¹ -> Na⁺¹Cl + Na⁺¹Cl^-1O₃^-2 + H₂⁺¹O^-2

To equalize the Oxidation Numbers of Cl and Na, 3 atoms of Cl and 6 atoms of Na are required. Thus,
3Cl₂ + 6NaOH -> 5NaCl + NaClO₃ + xH₂O
By inspection x = 3
∴ 3Cl₂ + 6NaOH -> 5NaCl + NaClO₃ + 3H₂O

I think this is correct, but if I have done something wrong please tell me so, as I'm new to this topic.
Thanks in advance.

 

[Borek]

No idea what you mean by "equalize the ON", specially in the context of sodium - ON for sodium doesn't change, and Na⁺ is only a spectator.

You have Cl(0) on the left and Cl(+1) and Cl(-1) on the right. This is disproportionation - the same element becomes both oxidized and reduced at the same time. Can you tell how many atoms of Cl get oxidized if 1 atom gets reduced?