Oxidation of alkene followed by Cu, heat

[Sat-P]

Homework Statement

Find product B

Relevant Equations

None

The answer I am getting is A but the answer given is D. I don't know why D because this is what I did. First I opened the alkene and then added OH on the less substituted carbon( Markonikov addition) and we know that Cu, Heat turns 3° alcohol to alkene so then I got an alkene.
Did I do something wrong or the answer is incorrect?

 

[TeethWhitener]

Wow that question is written in an incredibly confusing way. I think you’re right, except for the part where you say Markovnikov addition puts the hydroxyl on the less substituted carbon. But I think that’s just a typo on your part, as you clearly understand in the next sentence that the product of the oxymercuration/reduction is a tertiary alcohol (the more substituted carbon, thus following Markovnikov’s rule). Other than that, yes, exposure of a tert alcohol to copper and heat should dehydrate the compound to an alkene (following Zaitsev’s rule).