Oxidation of MnCl2 by NaBiO3: 5.0g Yields How Many Grams?

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Sodium bismuthate (NaBiO3) oxidizes MnCl2 to MnO4 and is consequently reduced to Bi(OH)3. How many grams of MnCl2 will be oxidized by 5.0 g of NaBiO3?

Could anyone please help me with this? I don't have a clue where to begin. :frown:
 
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Begin by writing out a balanced equation for this redox system.