Oxidisation of methanoic acid by kmno4

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SUMMARY

The discussion centers on the oxidation of methanoic acid (formic acid) by potassium permanganate (KMnO4) under acidic conditions, leading to the formation of carbon dioxide (CO2) and water. It highlights the unique behavior of methanoic acid compared to ethanoic acid (acetic acid) and ethanedioic acid (oxalic acid), with the latter also undergoing oxidation to CO2. The confusion arises from the differing oxidation pathways and the role of functional groups, particularly the presence of the -CHO group in methanoic acid. The discussion emphasizes the need for a clear understanding of the oxidation mechanisms involved.

PREREQUISITES
  • Understanding of organic chemistry oxidation reactions
  • Familiarity with potassium permanganate (KMnO4) as an oxidizing agent
  • Knowledge of carboxylic acids and their functional groups
  • Basic grasp of reaction mechanisms in organic chemistry
NEXT STEPS
  • Research the oxidation mechanisms of methanoic acid using KMnO4
  • Study the differences in oxidation pathways between methanoic acid and ethanoic acid
  • Explore the decomposition of oxalic acid and its oxidation to CO2
  • Learn about the role of functional groups in organic oxidation reactions
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Chemistry students, organic chemists, and anyone interested in the mechanisms of oxidation reactions in organic compounds.

timetraveller123
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i was reading through my alkene notes and it said for strong oxidation of alkenes in acidic conditions results in formation of ketone , carboxylic acid or carbondioxide and water. But my notes doesn't detail the mechanism so i found some videos explaining how ketones and carboxylic acid may be formed . and from what i understand if the oxidation process results in formation of methanoic acid , it is further oxidised into CO2 and water. many website just state this . i am curious why it only happens to methanoic acid and not like ethanoic acid . Some websites said it is because of the hydrogen being the r group but if that is true then why is ethandioic acid also oxidised by kmno4 into CO2 and water. I am really confused. it would be really helpful if someone could explain this or could link to a website with the mechanism(it helps me to understand better). I am sorry if i don't make sense.
 
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Methanoic acid is a bit similar in its properties to aldehydes (look at the molecule, can you see the -CHO group?)

I believe oxalic acid is a very specific case, not necessarily following rules that hold for most organic compounds.
 
thats the thing i haven't learned about aldehydes yet many websites said the same thing but then why does it work for ethandioc acid it does not have coh group
 
You do understand that oxalic acid and ethanedioic acid are the same substance and I already addressed your question?
 
ya i do but i don't quite get what you mean by that statement as in why that exception for oxalic acidedit :
is there anywhere i can look up for the mechanism of this oxidisation
 
It certainly is possible to decompose oxalic acid into CO and CO2. That's a classic method to produce CO in the laboratory. It is also possible to oxidize oxalic acid to CO2. That is basically the mechanism behind chemiluminescent lightsticks.
 
Somewhat specific but I wouldn't say "very specific".
Under the oxidation conditions like KMnO4, most C-C bonds are not oxidized. So CH3COOH is not oxidized. However, some C-C bonds are weakened - HOOC-COOH among them, but I remember there are others. Don't quite remember which others, though.
 

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