Oxidisation of methanoic acid by kmno4

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Discussion Overview

The discussion revolves around the oxidation of methanoic acid (formic acid) by potassium permanganate (KMnO4), exploring the mechanisms involved and the differing behaviors of various carboxylic acids during oxidation. Participants express confusion regarding why methanoic acid is oxidized to carbon dioxide and water, while other acids like ethanoic acid do not undergo the same transformation under similar conditions.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant notes that strong oxidation of alkenes in acidic conditions can lead to the formation of ketones, carboxylic acids, or carbon dioxide and water, but seeks clarification on the specific case of methanoic acid.
  • Another participant points out the structural similarity of methanoic acid to aldehydes, suggesting this may influence its oxidation behavior.
  • There is confusion regarding the oxidation of ethanedioic acid (oxalic acid) and its ability to be oxidized to carbon dioxide, despite not containing an aldehyde group.
  • A participant mentions that oxalic acid can decompose into carbon monoxide and carbon dioxide, indicating a potential pathway for its oxidation.
  • One participant states that under KMnO4 oxidation conditions, most C-C bonds are not oxidized, which may explain why ethanoic acid does not undergo the same transformation as methanoic acid.

Areas of Agreement / Disagreement

Participants express differing views on the oxidation mechanisms of methanoic acid and ethanedioic acid, with no consensus reached on the reasons behind their differing behaviors during oxidation.

Contextual Notes

Participants reference various oxidation mechanisms and structural properties of acids, but the discussion lacks clarity on specific conditions and assumptions that may influence the outcomes of the oxidation processes.

timetraveller123
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i was reading through my alkene notes and it said for strong oxidation of alkenes in acidic conditions results in formation of ketone , carboxylic acid or carbondioxide and water. But my notes doesn't detail the mechanism so i found some videos explaining how ketones and carboxylic acid may be formed . and from what i understand if the oxidation process results in formation of methanoic acid , it is further oxidised into CO2 and water. many website just state this . i am curious why it only happens to methanoic acid and not like ethanoic acid . Some websites said it is because of the hydrogen being the r group but if that is true then why is ethandioic acid also oxidised by kmno4 into CO2 and water. I am really confused. it would be really helpful if someone could explain this or could link to a website with the mechanism(it helps me to understand better). I am sorry if i don't make sense.
 
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Methanoic acid is a bit similar in its properties to aldehydes (look at the molecule, can you see the -CHO group?)

I believe oxalic acid is a very specific case, not necessarily following rules that hold for most organic compounds.
 
thats the thing i haven't learned about aldehydes yet many websites said the same thing but then why does it work for ethandioc acid it does not have coh group
 
You do understand that oxalic acid and ethanedioic acid are the same substance and I already addressed your question?
 
ya i do but i don't quite get what you mean by that statement as in why that exception for oxalic acidedit :
is there anywhere i can look up for the mechanism of this oxidisation
 
It certainly is possible to decompose oxalic acid into CO and CO2. That's a classic method to produce CO in the laboratory. It is also possible to oxidize oxalic acid to CO2. That is basically the mechanism behind chemiluminescent lightsticks.
 
Somewhat specific but I wouldn't say "very specific".
Under the oxidation conditions like KMnO4, most C-C bonds are not oxidized. So CH3COOH is not oxidized. However, some C-C bonds are weakened - HOOC-COOH among them, but I remember there are others. Don't quite remember which others, though.
 

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