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Homework Help: Parallel axis theorem and moment of inertia

  1. Oct 2, 2007 #1
    1. The problem statement, all variables and given/known data
    A thin rectangular sheet of steel is 0.30m by 0.40m and has mass 0.470kg. Find the moment of inertia about an axis that is perpendicular to the plane of the sheet and that passes through one corner of the sheet.

    2. Relevant equations
    Parallel axis theorem:
    Ip = Icm + Md^2
    Rectangular plate(but not thin):
    Icm = 1/12 M(a^2 + b^2) << where a and b are the sides of the rectangle

    3. The attempt at a solution

    Ip = 1/12((0.30)^2 + (0.40m)^2) + (0.470kg)((0.15m)^2 + (0.20m)^2)
    Ip = (0.0208333 + 0.029375)kg * m^2
    Ip = 0.05021 kg * m^2
  2. jcsd
  3. Oct 2, 2007 #2


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    Homework Helper

    you didn't multiply by M... 1/12M (a^2 + b^2)
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