Parallel Plate Capacitor

  • Thread starter Boozehound
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  • #1
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A parallel-plate capacitor has an area of 4.77 cm2, and the plates are separated by 1.06 mm with air between them. It stores a charge of 403 pC. What is the potential difference across the plates of the capacitor?

alright so i changed the area to .0477m^2. then i changed the distance between the plates to .00106m. i used 1.00054 as the dielectric constant. and i changed the charge to 403E-12C.

then i took 403E-12=((1.00054)(8.85E-12)(.0477)/(.00106))V

and i get V to equal 1.01V and its wrong. any help is appreciated.
 

Answers and Replies

  • #2
Dick
Science Advisor
Homework Helper
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For one thing, 4.77 cm^2 is 0.000477 m^2.
 

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