Parametric equation to cartesian

[Mrencko]

Homework Statement

I have this equation and i need to find the cartesian equation, so i apreciate your help

Homework Equations

X=cost ' y=2sin2t

The Attempt at a Solution

I am usign this [/B]
Sin2t=2costsint
So x+y/2=cost+2costsint
But i don't know what to do after,
I also try to solve that this way
Y/2=sin2t
Y/2=2costsint then sint=y/(4cost)
Y/2=2((x)y/4x)
When i isolate y i get y/y=3x-2

 

[Mark44]

Homework Statement

I have this equation and i need to find the cartesian equation, so i apreciate your help

Homework Equations

X=cost ' y=2sin2t

The Attempt at a Solution

I am usign this [/B]
Sin2t=2costsint
So x+y/2=cost+2costsint
But i don't know what to do after,
I also try to solve that this way
Y/2=sin2t
Y/2=2costsint then sint=y/(4cost)
Y/2=2((x)y/4x)
When i isolate y i get y/y=3x-2

So y = 4sin(t)cos(t). What is y/x?

Ideally, you want to get something that involves sin²(t) + cos²(t), which equals 1, and eliminates the parameter t.

 

[Mrencko]

Thanks for the help i juts figure out how to get rid of that parameter 1-cos alll div by 2

 

[Mark44]

Thanks for the help i juts figure out how to get rid of that parameter 1-cos alll div by 2

I doubt that will work.

 

[Mrencko]

y=4xsint==>y^2=16x^2(1(cost)^2)=y^2=16x^2(1-x^2)

 

[Mrencko]

Forget about div for 2

 

[Mark44]

y=4xsint==>y^2=16x^2(1(cost)^2)=y^2=16x^2(1-x^2)

With one correction, that works. Where you have y² = 16x²(1(cost)^2), it should be y² = 16x²(1 - cos²(t)). Otherwise, what you ended with is the same as I got.

 

[Mrencko]

Thanks that's it Sorry pal i have anoter problem i am doing x=sect y=tant
So what i need to do use the 1+tan^2=sec^2
Or use the sin/cos=tan and 1/cos = sec? I can get the solution

 

[LCKurtz]

Thanks that's it Sorry pal i have anoter problem i am doing x=sect y=tant
So what i need to do use the 1+tan^2=sec^2
Or use the sin/cos=tan and 1/cos = sec? I can get the solution

Using $1 + \tan^2\theta = \sec^2\theta$ is the obvious choice. But you should post new questions in new threads if you don't want to have your hand slapped by a moderator.

 

[Mark44]

Thanks that's it Sorry pal i have anoter problem i am doing x=sect y=tant
So what i need to do use the 1+tan^2=sec^2
Or use the sin/cos=tan and 1/cos = sec? I can get the solution

This is a new problem, so please start a new thread.