Partial Derivative of atan(xy/(1+x^2+y^2)^0.5)

In summary, the formula for finding the partial derivative of atan(xy/(1+x^2+y^2)^0.5) is ∂/∂x (atan(xy/(1+x^2+y^2)^0.5)) = (y(1+x^2+y^2)^0.5 - xy(1+x^2+y^2)^-0.5) / (1+x^2+y^2). This represents the rate of change of the function with respect to the variable being differentiated and can be positive, negative, or zero. The derivative can be simplified using trigonometric identities and algebraic manipulations, and it is useful in various real-world applications to optimize processes, solve optimization problems,
  • #1
MrWarlock616
160
3

Homework Statement



Prove that if ##z=\arctan(\frac{xy}{\sqrt(1+x^2+y^2)})## , then:

##\frac{\partial^2 z}{\partial x \partial y}=\frac{1}{(1+x^2+y^2)^\frac{3}{2}} ##

Homework Equations



##\frac{d}{d x} (\arctan(x)) = \frac{1}{1+x^2}##

The Attempt at a Solution



Differentiating z partially w.r.t y, I got:

## \frac{\partial z}{\partial y} = \frac{x^3+x}{(1+x^2+y^2)^\frac{3}{2} (1+x^2+y^2+x^2y^2)} ##

I'm pretty sure my working till here is correct. But differentiating again w.r.t x would be disastrous. Help me please. :)
 
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  • #2
Hi MrWarlock616! :smile:

You can cancel a (1 + x2), top-and-bottom :wink:
 
  • #3
EDIT: -nvm got it-
 

1. What is the formula for finding the partial derivative of atan(xy/(1+x^2+y^2)^0.5)?

The formula for finding the partial derivative of atan(xy/(1+x^2+y^2)^0.5) is:∂/∂x (atan(xy/(1+x^2+y^2)^0.5)) = (y(1+x^2+y^2)^0.5 - xy(1+x^2+y^2)^-0.5) / (1+x^2+y^2)

2. How do you interpret the result of a partial derivative of atan(xy/(1+x^2+y^2)^0.5)?

The result of a partial derivative of atan(xy/(1+x^2+y^2)^0.5) represents the rate of change of the function with respect to the variable being differentiated (in this case, x). It shows how the function changes as the value of x changes, while holding all other variables constant.

3. Can the partial derivative of atan(xy/(1+x^2+y^2)^0.5) be negative?

Yes, the partial derivative of atan(xy/(1+x^2+y^2)^0.5) can be negative. The derivative can be positive, negative, or zero depending on the values of x, y, and (1+x^2+y^2)^0.5.

4. Is it possible to simplify the partial derivative of atan(xy/(1+x^2+y^2)^0.5)?

Yes, the partial derivative of atan(xy/(1+x^2+y^2)^0.5) can be simplified by using trigonometric identities and algebraic manipulations. However, the simplified form may not always be more useful or intuitive than the original form.

5. How is the partial derivative of atan(xy/(1+x^2+y^2)^0.5) useful in real-world applications?

The partial derivative of atan(xy/(1+x^2+y^2)^0.5) can be useful in many real-world applications, such as in physics, engineering, and economics. It can help determine the rate of change of a variable in a multivariable system, which can be used to optimize processes, solve optimization problems, and make predictions about the behavior of the system.

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