Partial derivative - why is it count like this?

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SUMMARY

The discussion centers on the calculation of the partial derivative of a function with respect to the variable α, as presented in John R. Taylor's "Classical Mechanics." The integral under consideration is \int\limits^{x_2}_{x_1}f\left(y+\alpha\eta,y^{\prime}+\alpha\eta^{\prime},x\right)\mbox{d}x. The resulting derivative is expressed as \frac{\partial f}{\partial\alpha}=\eta\frac{\partial f}{\partial y}+\eta^{\prime}\frac{\partial f}{\partial y^{\prime}}, which incorporates both \frac{\partial f}{\partial y} and \frac{\partial f}{\partial y^{\prime}} due to the application of the chain rule, as y and y' are functions of α. This highlights the necessity of recognizing the dependencies of variables when differentiating.

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Homework Statement


I have John R Taylor "Classical mechanics" part 1, and I have an integral:
[tex]\int\limits^{x_2}_{x_1}f\left(y+\alpha\eta,y^{\prime}+\alpha\eta^{\prime},x\right)\mbox{d}x[/tex]
and here is count derivative of underintegral function in [tex]\alpha[/tex]
[tex]\frac{\partial f\left(y+\alpha\eta,y^{\prime}+\alpha\eta^{\prime},x\right)}{\partial\alpha}=\eta\frac{\partial f}{\partial y}+\eta^{\prime}\frac{\partial f}{\partial y^{\prime}}[/tex]
why there is suddenly [tex]\frac{\partial f}{\partial y^{\prime}}[/tex] and [tex]\frac{\partial f}{\partial y}[/tex], while this derivative is by [tex]\alpha[/tex] - why not only [tex]\eta,\eta^{\prime}[/tex]?

Homework Equations


I was thinking about function composition derivative, but it didnt helped me.

The Attempt at a Solution


Nothing, I couldn't do anything with this, I don't know why this is count like this, please help;] thanks!
 
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[tex]f=f(y,y',x)[/tex]

Now if you replace [tex]y=\bar{y}+\alpha\eta[/tex] then y becomes a function of alpha, which means that you have to use the chain rule.

Try choosing an explicit non-linear expression for f if that makes it more clear. For example f(y,y',x) = y2 + y'2
 

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