Partial Derivatives and the Linear Wave Equation

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The discussion focuses on the use of partial derivatives in the context of the linear wave equation. It clarifies that when evaluating the slope of the tangent at a specific time, time must be held constant, necessitating the use of a partial derivative with respect to position. The relationship between displacement, position, and time is emphasized, indicating that y is dependent on both x and t. If both x and t were allowed to change, a different derivative, such as the directional or covariant derivative, would be required. Understanding these concepts is crucial for accurately analyzing wave behavior in physics.
Taulant Sholla
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Homework Statement


I'm reading through the derivations of the linear wave equation. I'm following everything, except the passage I highlighted in yellow in the below attachment:
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Homework Equations


I'm not understanding why partials must be used because "we evaluate this tangent at a particular instant of time."

The Attempt at a Solution


It seems if x, y, and t were all changing then there'd be a need for a partial. As stated in the highlighted text, I'm not getting it. Any help is appreciated.
 
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The displacement y of the string from its equilibrium position (y=0) is a function of both x and t - it depends on where along the string you look, and on the time at which you look at it. Figure 16.19 shows the position of the string at a given time t. So when you find the slope of the tangent at this time t, you are holding the time constant. That means that you must take the partial derivative of y with respect to x - the definition of a partial derivative requires you to hold fixed all independent variables other than the one by which you differentiate.

On your point 3, it is because you are holding t fixed that you need to use the partial derivative. Note that x and t are your independent variables, and that y is the dependent variable. were you to allow both x and t to change, you would need a different kind of derivative that you will probably not have studied yet, and its physical interpretation would be quite different.
 
Very helpful - thank you so much! What kind of derivative is needed if x and t were both changing?
 
It is called the directional derivative, or the covariant derivative.
 
Thank you again.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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