Partial Derivatives for P, S, T in Differential Calculus

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SUMMARY

The discussion focuses on calculating the partial derivative of pressure (P) with respect to volume (V) at fixed temperature (T) and entropy (S) using the equation P = TS / (4V). The derived formula for the partial derivative is confirmed as ∂P/∂V = -TS / (4V²). The conversation also explores the implications of varying T and S on the derivative, concluding that the derived expression holds true under the specified conditions.

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  • Knowledge of the mathematical manipulation of equations
  • Experience with the application of the chain rule in calculus
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Homework Statement




I'm looking for [tex]\frac{\partial{P}}{\partial{V}}[/tex] at fixed T and fixed S.


Homework Equations



[tex]P=\frac{TS}{4V}[/tex]

The Attempt at a Solution



[tex]\frac{dP}{dV}=\frac{\partial{P}}{\partial{V}}+\frac{\partial{P}}{\partial{T}}\frac{dT}{dV}+\frac{\partial{P}}{\partial{S}}\frac{dS}{dV}[/tex]

[tex]\frac{\partial{P}}{\partial{V}}=-\frac{TS}{4V^2}[/tex]

[tex]\frac{\partial{P}}{\partial{T}}=\frac{S}{4V}[/tex]

[tex]\frac{\partial{P}}{\partial{S}}=\frac{T}{4V}[/tex]

[tex]\frac{dP}{dV}=\frac{\partial{P}}{\partial{V}}+\frac{\partial{P}}{\partial{T}}\frac{dT}{dV}+\frac{\partial{P}}{\partial{S}}\frac{dS}{dV}=-\frac{TS}{4V^2}+\frac{S}{4V}\frac{dT}{dV}+\frac{T}{4V}\frac{dS}{dV}[/tex]

At constant T, I get this: [tex]\frac{dP}{dV}=-\frac{TS}{4V^2}+\frac{T}{4V}\frac{dS}{dV}[/tex]

At constant S, I get this: [tex]\frac{dP}{dV}=-\frac{TS}{4V^2}+\frac{S}{4V}\frac{dT}{dV}[/tex]

What do I do about the other differentials: [tex]\frac{dS}{dV}[/tex] and [tex]\frac{dT}{dV}[/tex]?

Wouldn't this also be true?

[tex]\frac{dS}{dV}=\frac{\partial{S}}{\partial{V}}+\frac{\partial{S}}{\partial{T}}\frac{dT}{dV}+\frac{\partial{S}}{\partial{P}}\frac{dP}{dV}[/tex]

[tex]\frac{dT}{dV}=\frac{\partial{T}}{\partial{V}}+\frac{\partial{T}}{\partial{S}}\frac{dS}{dV}+\frac{\partial{T}}{\partial{P}}\frac{dP}{dV}[/tex]
 
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You want to find [tex] \frac{\partial{P}}{\partial{V}}[/tex]

and your second line is

[tex] \frac{\partial{P}}{\partial{V}}=-\frac{TS}{4V^2}[/tex]

So... you're done?
 


Office_Shredder said:
You want to find [tex] \frac{\partial{P}}{\partial{V}}[/tex]

and your second line is

[tex] \frac{\partial{P}}{\partial{V}}=-\frac{TS}{4V^2}[/tex]

So... you're done?


Yes. That's at constant T and constant S.

Is it the same if T is constant and S is not constant? Or vice-versa?
 

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