Partial Derivatives in Differential Calculus: Need Help

  • Context: Graduate 
  • Thread starter Thread starter jem05
  • Start date Start date
  • Tags Tags
    Calculas Differential
Click For Summary
SUMMARY

The discussion centers on the construction of a function from R² to R that possesses partial derivatives of all orders in a neighborhood of (0,0) while being discontinuous at the origin. The proposed function is defined as f(x,y) = 0 at the origin and f(x,y) = (cos t, sin t) otherwise, where x = Rcos(t) and y = Rsin(t). The user seeks clarification on ensuring the existence of all orders of partial derivatives for this function.

PREREQUISITES
  • Understanding of partial derivatives in multivariable calculus
  • Familiarity with continuity and discontinuity concepts
  • Knowledge of polar coordinates and their application in functions
  • Basic principles of differential calculus
NEXT STEPS
  • Research the properties of functions with discontinuous points and their derivatives
  • Study the implications of the existence of higher-order partial derivatives
  • Explore examples of functions that are differentiable but not continuous
  • Learn about the application of polar coordinates in analyzing multivariable functions
USEFUL FOR

Students and professionals in mathematics, particularly those studying multivariable calculus, as well as educators seeking to understand the nuances of continuity and differentiability in functions.

jem05
Messages
54
Reaction score
0
im trying to get a function R^2 --> R
whose partial derivatives of all orders exist in a neighborhood of (0,0) but it, itself, is not continuous at the origin.
thing is, i think I am thinking of the question wrong because, I am getting examples and checking if partial der. exist but how can i ensure that all the orders do so,...?
any ideas? thx
 
Physics news on Phys.org
Let f(x,y) = 0 at the origin,
= (cos t , sin t) otherwise ( where x = Rcost ,y =Rsint).
 
isnt that the same as f(r,t) = cost , with 0 if r = 0?
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 21 ·
Replies
21
Views
6K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
20
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K