Partial Differential/Integration Arbitrary Functions

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The discussion focuses on solving the partial differential equation \(\frac{\partial u}{\partial y}=\frac{x}{\sqrt{1+y^2}}\) for the function \(u(x,y,z)\). The solution is derived using integration techniques, leading to \(u(x,y,z)=x\sinh^{-1}y+f(x,z)\), where \(f(x,z)\) represents a more general form than \(f(x)+g(z)\). The participants emphasize that \(f(x,z)\) allows for greater flexibility in representing solutions compared to the sum of two separate functions.

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Use integration to find a solution involving one or more arbirary functions
[tex]\frac{\partial u}{\partial y}=\frac{x}{\sqrt{1+y^2}}[/tex]
for a function [itex]u(x,y,z)[/itex]
[tex]u(x,y,z)=x\int \frac{dy}{\sqrt{1+y^2}}[/tex]
let [itex]y=\sinh v[/itex]
[tex]u(x,y,z)=x\int \frac{\cosh v\: dv}{\sqrt{1+\sinh ^2v}}[/tex]
[tex]u(x,y,z)=x\sinh ^{-1}y+f(x,z)[/tex]
So here's the question. Why is the solution with an arbirary function [itex]f(x,z)[/itex] and not two arbitrary functions [itex]f(x)+g(z)[/itex]? What's the difference?
 
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##f(x,z)## is more general than ##f(x) + g(z)##.

For example, how would you convert a function like ##f(x,z) = x^z## to the form ##f(x) + g(z)##?
 
AlephZero said:
##f(x,z)## is more general than ##f(x) + g(z)##.

For example, how would you convert a function like ##f(x,z) = x^z## to the form ##f(x) + g(z)##?

Good point. But how can i explain that in a mathematical language?
 

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