Partial Fraction Decomposition of Complex Fractions

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 2K views
Dustinsfl
Messages
2,217
Reaction score
5
$$
\frac{1}{z^2(1-z)} = \frac{A}{z^2}+\frac{B}{1-z}
$$I can't figure out how to decompose this fraction.
 
Physics news on Phys.org
dwsmith said:
$$
\frac{1}{z^2(1-z)} = \frac{A}{z^2}+\frac{B}{1-z}
$$I can't figure out how to decompose this fraction.

You're missing a term. The decomposition should be of the form

\[ \frac{1}{z^2(1-z)} = \frac{A}{z}+\frac{B}{z^2}+\frac{C}{1-z} \]

Is it also to be assumed that $A,B,C\in\mathbb{C}$?