Partial pressure of reagent in reaction

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SUMMARY

The discussion focuses on calculating the partial pressure of the product AB4 in the reaction A(g) + 2B2(g) -> AB4(g) at equilibrium, given an equilibrium constant K(T=298) of 10. The initial conditions include 1 mol of A and 1 mol of B at 1 bar and 298K. Using the ICE table approach and stoichiometric relationships, the calculated partial pressure of AB4 at equilibrium is determined to be 0.268 bar.

PREREQUISITES
  • Understanding of ideal gas behavior
  • Knowledge of equilibrium constants and their significance
  • Familiarity with the ICE table method for equilibrium calculations
  • Basic stoichiometry related to chemical reactions
NEXT STEPS
  • Study the application of Dalton's Law in gas mixtures
  • Learn how to derive equilibrium expressions from chemical reactions
  • Explore the use of ICE tables in complex equilibrium problems
  • Investigate the impact of temperature and pressure on equilibrium constants
USEFUL FOR

Chemistry students, particularly those studying chemical equilibrium, reaction kinetics, and gas laws, will benefit from this discussion.

Denver Dang
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Homework Statement


I have the reaction:

A(g) + 2B2(g) -> AB4(g)

The equilibrium constant K(T=298) = 10, and all gases are ideal.

So the two reagents A and B are mixed together at 1 bar and T = 298K, with the quantities 1 mol of A and 1 mol of B.

Now I have to find the partial pressure of AB4 when there is equilibrium in the reaction.

Homework Equations



?

The Attempt at a Solution


I've looked at Dalton's Law, but nothing I did seemed to make sense. So I'm kinda stuck.

I know the result should be: 0,268 bar.

So, could anyone give me a hint ?Thanks in advance.

Regards.
 
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Have you tried ICE table approach?

This is not very difficult - you have to calculate amounts of substances at equilibrium. Write expression for K and think how concentrations of all substances change during the reaction - they are linked by stoichiometry.
 
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