Particle Collision: 3.00kg & 4.00kg Particles

[cgarr017]

Particle Collision Two A collision occurs between a 3.00 kg particle traveling with velocity v = (-4.00 m/s) i + (-5.00 m/s) j and a 4.00 kg particle traveling with velocity v = (5.60 m/s) i + (-1.80 m/s) j. The collision connects the two particles. What then is their velocity in each of the following notations?
(a) unit-vector notation
( wrong check mark m/s ) i + ( wrong check mark m/s ) j
(b) magnitude-angle notation
m/s angle ° (counterclockwise from the positive x axis)

I would show an attempt at the solution but i have no idea what the formulas are or where to start

 

[cgarr017]

nobody?

 

[ipodlover]

Hey a little late, but I think for this one you have to use

p= momentum= (mass*velocity)

vf = (p1 + p2)/(m1+m2)

for angle, use tangent.

tan(o) = p2/p1

(o) = tan^-1(p2/p1).


With respect to vector notation, i think you just add and subtract, but for angle use Pythagoras, cause you will need v1, and v2 as a quantity.