1. The problem statement, all variables and given/known data particle moving in the semi infinite potentail well set up and solve SE for the system assume E<Vo 2. Relevant equations (-h2/2m) d2[itex]\psi[/itex]/dx2 +v(x)[itex]\psi[/itex]=E[itex]\psi[/itex] 3. The attempt at a solution so in reagion one its infinite so [itex]\psi[/itex]=0. reagion 2 is what i am confused about. looking throught the book i saw the gen solution for inside the well to be [itex]\psi[/itex]=Ae(ikx)+Be-(ikx) but for this problem its Acos(kx)+Bsin(kx) in the book does not really show how it finds the gen solution. im just a little confused on how you would solve the SE well i know for inside v=0 and i plug that into SE and from that the book just goes to the gen solution thanks edit after looking at lecture note i see he uses the cos for the inside , but in they book for the same infinite pot well they use the e^ are they the same?