Particle Motion (Astrophysics)

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SUMMARY

The discussion focuses on the problem of determining when a particle p, moving at the speed of light (v1 = c), catches up to another particle q, which moves at a speed v2 dependent on the distance r. The equation governing v2 is given as v2(r) = v0hr, where h is the Hubble constant and v0 is the initial velocity. The solution involves setting up a differential equation, separating variables, and integrating to find the relationship between r and time. The application of the Lambert W function is noted as a method to solve the final step of the problem.

PREREQUISITES
  • Understanding of Special Relativity and its implications on mass and velocity.
  • Familiarity with differential equations and integration techniques.
  • Knowledge of the Hubble constant and its role in astrophysics.
  • Experience with the Lambert W function for solving equations.
NEXT STEPS
  • Study the application of the Lambert W function in solving transcendental equations.
  • Explore the implications of Special Relativity on particle motion and reference frames.
  • Investigate the relationship between velocity, distance, and time in astrophysical contexts.
  • Learn about differential equations in physics, particularly in motion problems.
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Students and professionals in astrophysics, physicists working with relativistic motion, and anyone interested in advanced mathematical modeling of particle dynamics.

Gregorski
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Homework Statement


This is new for me, so forgive me my clumsiness. I am working on the following problem:
A particle p is moving with a velocity v1 = c (speed of light) towards an object q, which is moving in the same direction with the speed v2, where v1>v2. Now, v2 is a function of the distance r between p and q. I need to find the time when p "catches up" with q.

Homework Equations


v2(r)= v0hr, where h - the Hubble constant, v0 - initial velocity, and r - distance between p and q

The Attempt at a Solution


Particle p will "catch up" with q when the distance between them is 0, so we have:
r - s =0 and r = s (1)
v2(r)= v0hr
Differential equation:
ds/dt = v0hr

Separating variables:
ds/r= v0h dt
Integrating:
log r = v0ht + c
r = ev0ht+c
r = ecev0ht
ec=R
r=Rev0ht

Plugging into (1)
Rev0ht = v1t

I am not sure how to proceed from here or if any of it makes sense.
 
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Gregorski said:

Homework Statement


This is new for me, so forgive me my clumsiness. I am working on the following problem:
A particle p is moving with a velocity v1 = c (speed of light) towards an object q, which is moving in the same direction with the speed v2, where v1>v2. Now, v2 is a function of the distance r between p and q. I need to find the time when p "catches up" with q.

Homework Equations


v2(r)= v0hr, where h - the Hubble constant, v0 - initial velocity, and r - distance between p and q

The Attempt at a Solution


Particle p will "catch up" with q when the distance between them is 0, so we have:
r - s =0 and r = s (1)
v2(r)= v0hr
Differential equation:
ds/dt = v0hr

Separating variables:
ds/r= v0h dt
Integrating:
log r = v0ht + c
r = ev0ht+c
r = ecev0ht
ec=R
r=Rev0ht

Plugging into (1)
Rev0ht = v1t

I am not sure how to proceed from here or if any of it makes sense.
Welcome to PF Gregorski!

There are two reference frames. The observer frame, relative to which q is moving at speed v2, and q's rest frame. It is not clear from the question as to the reference frame in which r or time is being measured.

According to Special Relativity, p must have 0 rest mass and must be moving at speed c relative to all inertial reference frames. The observer and q would measure the time for p to reach q differently.

AM
 
Andrew,
Thank you for your input; you're absolutely right there are two frames. I managed to do the last step by applying Lambert W function.

Greg
 

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