Particle moving in electromagnetic field - converting units

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SUMMARY

The discussion focuses on the force exerted on a moving charged particle in a magnetic field, specifically the equation F = qv × B, which produces a centripetal force. The relationship between momentum and magnetic field strength is established as pc = ABρ, where B is the magnetic field strength in Tesla and ρ is the radius of the circular orbit in meters. The constant A, expressed in GeV/T-m for a proton, is derived from the charge and speed of light, with the value calculated as A = qc = 1.6 x 10^-19 C x c. The conversion of units from Joules to GeV is emphasized as a critical step in the calculations.

PREREQUISITES
  • Understanding of Lorentz force and its application in electromagnetism
  • Familiarity with the concepts of momentum and centripetal force
  • Knowledge of unit conversions, particularly from Joules to GeV
  • Basic understanding of circular motion in physics
NEXT STEPS
  • Learn about the Lorentz force and its implications in charged particle dynamics
  • Study the derivation of the relationship between momentum and magnetic fields in particle physics
  • Explore unit conversion techniques, specifically converting between Joules and GeV
  • Investigate the principles of circular motion and its applications in electromagnetic fields
USEFUL FOR

Students in physics, particularly those studying electromagnetism and particle dynamics, as well as educators looking to enhance their understanding of charged particle behavior in magnetic fields.

bossman27
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Homework Statement


Show that the force on a moving charged particle F = qv × B
from a magnetic field pointing perpendicular to the velocity produces a centripetal force and that this is equivalent to the equation pc = ABρ, where B is the magnetic field strength (in Tesla) and ρ is the radius of the circular orbit (in meters). If we express p in GeV/c, what
is the value of the constant A (which has units GeV/T-m) for a proton?


Homework Equations





The Attempt at a Solution



I had no trouble with the first part of the problem. Since v is perpendicular to B, I just used F=(mv^2)/r and then multiplied both sides by c to get pc = qcB(rho). Now I have A = qc = 1.6x10^-19 C x c, however this is my first time working with eV units and am a bit lost on how to go about converting 'charge*c' to GeV/T-m.
 
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Your first step is to demonstrate circular motion.

After that, do your calculation in GeV from the get-go. note that mc2=0.938GeV

[tex]evB=\frac{mv^2}{r}=\frac{p^2}{mr}=\frac{(pc)^2}{mc^2r}[/tex]

Or do the dimensional analysys on your units (Cm/s) to make sure they come out to Joules/(Tesla-meters) then just convert the Joules to GeV by the usual conversion factor.
 

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