Particle potential energy - acceleration?

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Homework Help Overview

The discussion revolves around the relationship between potential energy and acceleration in the context of particle dynamics. Participants are exploring the implications of the equation for potential energy changes and its connection to force and acceleration.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to relate potential energy changes to force and acceleration, questioning the validity of their calculations and the signs of their results. There is also a focus on the formal relationships between these physical quantities.

Discussion Status

Several participants are actively engaging with the mathematical relationships involved, with some providing insights into derivatives and their implications. There is a recognition of potential errors in sign and calculations, indicating a productive exploration of the topic.

Contextual Notes

There appears to be some uncertainty regarding the values used in calculations and the assumptions about the signs of forces and accelerations. Participants are also reflecting on the implications of their results in terms of physical meaning.

reminiscent
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Homework Statement


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Homework Equations


ΔU = Uf - Ui

The Attempt at a Solution


Would I have to make the left side of the equation equal to m*a*x? Is the x on the left side equal to -100 m?
 
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What's the formal relationship between force and potential energy?
 
gneill said:
What's the formal relationship between force and potential energy?
The derivative of potential energy equals force (Fx = -dU/dx). So the derivative would turn it to be: -C/(x2). Then it's just plugging in from there, correct?
 
gneill said:
What's the formal relationship between force and potential energy?
For the acceleration, I got -0.0011 m/s^2. Does that seem too small?
 
reminiscent said:
For the acceleration, I got -0.0011 m/s^2. Does that seem too small?
The magnitude looks good but its sign is suspect. Check the details of your derivative.
 
gneill said:
The magnitude looks good but its sign is suspect. Check the details of your derivative.
Why isn't it negative, though? Since Fx = -dU/dx, wouldn't it be Fx = -(-C*-1*x-2)? It will still be negative.
 
reminiscent said:
Why isn't it negative, though? Since Fx = -dU/dx, wouldn't it be Fx = -(-C*-1*x-2)? It will still be negative.
Oops. You're quite right. My mistake. o:)
 

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