For a particle in simple harmonic motion, show that vmax = (pi/2) vaverage, where vaverage is the average speed during one cycle of the motion.
v(t) = -vmaxsin(wt + phi)
vmax = 2piA/ T = wA
The Attempt at a Solution
I'm really not sure at all how to start this, but Im guessing there really wouldn't be a numerical value just theory based?