Particles under constant acceleration

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SUMMARY

The discussion focuses on a physics problem involving a car that decelerates uniformly at -5.60 m/s² for 4.20 seconds, covering a distance of 62.4 meters before hitting a tree. The correct approach to find the speed at impact involves using the equations of motion, specifically Vf = Vi + at, where the initial velocity (Vi) is calculated as 26.6 m/s. The average velocity is determined to be 14.9 m/s, leading to a final velocity (Vf) of 3.10 m/s at the moment of impact, correcting the initial miscalculation.

PREREQUISITES
  • Understanding of kinematic equations, specifically Vf = Vi + at
  • Knowledge of average velocity calculations (Vavg = x/t)
  • Familiarity with concepts of uniform acceleration and deceleration
  • Ability to manipulate algebraic equations to solve for unknowns
NEXT STEPS
  • Study the derivation and application of kinematic equations in physics
  • Learn how to calculate average velocity and its significance in motion problems
  • Explore the effects of different types of acceleration on motion
  • Practice solving real-world physics problems involving uniform acceleration
USEFUL FOR

Students studying physics, particularly those focusing on kinematics, as well as educators seeking to clarify concepts of motion and acceleration in practical scenarios.

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Homework Statement



Okay, wordy. Read through though, please :smile:

The driver of a car slams on the brakes when he sees a tree blocking the road. The car slows uniformly with an acceleration of -5.60 m/s^2 for 4.20s, making straight skid marks 62.4m long ending at the tree. At what speed does it hit the tree?

Homework Equations



Vf=Vi+at

The Attempt at a Solution



So I saw I had a=-5.60m/s^2, t=4.20s, xf=62.4m, and Vf=0 (since after he hit the tree, he stopped).

So I plugged them into Vf=Vi+at (or rather Vi=Vf-at), or 0-(-5.60)*4.20, to give 23.52 m/s. It seems wrong, though. Suggestions or advice?
 
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you jumped ahead by setting Vf to 0, you simply want to solve for Vf to find out what speed it is going when it hits the tree (as the question asks).

they also give you a time and distance, so you have an average velocity to help figure out the initial velocity in terms of the final velocity (or vice versa)After it hits the tree, it experiences another negative acceleration as it crumples against the tree, each piece of the car at different rates; but that would be a different problem all together.
 
Last edited:
Oh...so I'm to find the average velocity, right? Umm...that's x/t, which is 62.4/4.20, which gives 14.9.

Then, I would have to find the initial velocity, uh huh? xf=xi+Vxit+1/2at^2...Vi=26.6.

Then Vavg=Vi+Vf/2 would come to play...14.9=26.6+x/2, gives a different answer, Vf=3.10m/s. It looks a little bit more correct, so thanks.
 

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