1. The problem statement, all variables and given/known data Determine which row of pascals triangle contains 3 consecutive entries that are in the ratio 1:2:3. 2. Relevant equations (n, k ) = n!/k!(n-k)! 3. The attempt at a solution (n,k):(n,k+1):(n,k+2) 1 : 2: : 3 What I did was cross multiply. 2 times (n,k) = 1 times (n,k+1) and 3 times (n,k+1) = 2 times (n,k+2) 2(n!/(k!(n-k)!) = n!/(k+1)!(n-k-1)! and 3(n!/(k+1)!(n-k-1)!) = 2(n!/(k+2)!(n-k-2)! I know that i should solve for n in the first equation then substitute n in the second equation to get n and k. I'm stuck on the algebra part.