Pascals's Principle and Airsoft?

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SUMMARY

This discussion centers on calculating the force exerted on a BB as it exits an airsoft gun barrel using Pascal's Principle and Hooke's Law. The user applies the formula F(1) = F(2) * (A1/A2) to relate the forces and areas involved in the piston mechanism. The conversation highlights the need for understanding fluid dynamics, particularly in relation to compressible flow, as air behaves differently than incompressible fluids. The user seeks validation of the equations used and explores alternative methods, such as Bernoulli's equation for compressible flow.

PREREQUISITES
  • Understanding of Hooke's Law and its application in spring mechanics
  • Familiarity with Pascal's Principle and its implications in fluid mechanics
  • Basic knowledge of pneumatic systems and their components
  • Introduction to fluid dynamics, particularly compressible flow concepts
NEXT STEPS
  • Study the application of Bernoulli's equation in compressible flow scenarios
  • Research the dynamics of pneumatic cylinders and their force calculations
  • Explore advanced fluid dynamics principles relevant to airsoft gun mechanics
  • Learn about experimental methods to measure force and pressure in pneumatic systems
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Engineers, airsoft enthusiasts, and hobbyists interested in the mechanics of airsoft guns and fluid dynamics principles related to pneumatic systems.

Chemical Bros
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Alright I was just thinking about the internals of an airsoft gun and I began to wonder how to calculate the force exerted on the BB as it leaves the barrel. Here is an image of the internals:

Link to image:

http://www.google.ca/imgres?imgurl=...age=1&ndsp=21&ved=1t:429,r:14,s:0&tx=60&ty=36

I then decided to use hooke's law for the force of the spring as that would be the force exerted on the piston. My next step, as I was never really taught fluid dynamics, was if I was to use Pascal's principle to calculate the force at the nozzle (black piece right before the BB).

F(1)=-kx

therefore (using pascal principle)

F(1)=F(2) * (A1/A2)

-kx=F(2)*(A1/A2)

F(2)=(-kx)/(A2/A1)

I looked up the principle and most of the time it says it works if its static and confined. My question is if the equation can be used in this circumstance or if there is another way to find the force exerted on the BB? I also came across this website:

http://www.engineeringtoolbox.com/pneumatic-cylinder-force-d_1273.html

Are these equations viable or would they not suit this type of piston/cylinder? Thanks in advance!
 
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