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Paschen-Back and Zeeman in different base

  1. Jul 18, 2013 #1
    Hello,

    In the image below, we see the result of the Zeeman and Paschen-Back effect in a magnetic field which we worked out, together with the exact result, described in different basesets (coupled J,mj and uncoupled mlms).


    fe8_zeemanpaschenback.png

    I understand that each effect can be better described in a different set, but I don't understand how that the result can be so 'wrong' compared to the exact result by using this different base.

    I thought it was possible to go from coupled to uncoupled and visa versa, doesn't this also mean that an effect has to give the same results in a different base? Where does these errors come from?


    I hope my question is clear enough :X
     
  2. jcsd
  3. Jul 18, 2013 #2

    DrDu

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    How exactly did you "work it out"? Do you refer to a perturbational treatment?
     
  4. Jul 18, 2013 #3
    yes.

    For example PB:

    H(0) = H_Bohr + H_Zeeman
    H(1) (perturbation Hamiltonian) = H_SO (spin orbit coupling)

    with H_Zeeman = b(l_z = g_e.s_Z

    and H_SO = l.s = 1/2(l_+s_- + l_-s_+) + l_z.s_z
     
  5. Jul 18, 2013 #4

    DrDu

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    What you probably did was not using different bases but different zeroth order hamiltonians which have the corresponding basefunctions as eigenstates.
    The perturbation series obtained starting from different zeroth order hamiltonians may differ dramatically. Using one H_0 already a first order correction may be sufficient to obtain a very good approximation to the exact eigenstates and energies while with another H_0 the perturbation series may be highly divergent.
     
  6. Jul 18, 2013 #5

    Ah yes, seems a fitting explanation, thanks! :)
     
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