Proving Path Independence: Evaluating the Integral on a Given Curve"

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SUMMARY

The discussion centers on proving the path independence of the vector field F defined as F = (4x^3y^2 + 2xy^3)i + (2x^4y - 3x^2y^2 + 4y^3)j. The curl of F was calculated and found to be zero, confirming path independence according to Stokes' theorem. The integral of F dot dr over the curve c, defined by r(t) = (t + sin(πt))i + (2t + cos(πt))j for 0 ≤ t ≤ 1, can be evaluated using a more convenient path due to this property.

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  • Understanding of vector fields and line integrals
  • Familiarity with Stokes' theorem
  • Knowledge of curl and gradient operations
  • Basic calculus, particularly integration techniques
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  • Study Stokes' theorem in detail and its applications in vector calculus
  • Learn how to compute line integrals for various paths
  • Explore the concept of curl and its significance in determining path independence
  • Practice evaluating integrals of vector fields over different curves
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Students and educators in calculus, particularly those focusing on vector calculus and line integrals, as well as anyone looking to deepen their understanding of path independence in vector fields.

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Homework Statement



show that F is path independent. Then evaluate the integral F dot dr on c, where c = r(t) = (t+sin(pi)t) i + (2t + cos(pi)t) j, 0<=t<=1

Homework Equations





The Attempt at a Solution



F = 4x^3y^2 + 2xy^3 i + 2x^4y - 3x^2y^2 + 4y^3 j

grad f = 12x^2y^2 + 2y^3 i + 2x^4 - 6x^2y + 12y^2 j not sure i need this

my instructor talked about numerouse way to determine path independace. which is the easiest
 
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You mean the line integral of F is path independent? All you have to do is show that the curl of F is zero. Then the result follows from Stoke's theorem.
 
ok so i found the curl of F
curl F = (8x^3y - 6xy^2 - 8x^3y + 6xy^2) = 0

but then the problem says to eval the integral F dot dr over the region c

when i dot them i got a extremely long expression. is this problem just a pain in the butt or did i make a boo boo
 
You've shown that the line integral is path independent, so you can choose a more convenient path to do the integration. What does the curve C look like? What are its endpoints?
 

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