- #1

jmm5872

- 43

- 0

The answer is supposed to be .81A.

y(t) = Ae^(t/2[tex]\tau[/tex])cos([tex]\omega[/tex]t)

I think I might just be confused about the wording of this problem. I know that the angular frequency of a pendulum only depends on gravity and the length of the string, therefore both pendulums will be exactly the same. So now I tried to plug in 300 seconds to the above equation for t, and set A to .5A. Now I am stuck, I don't know how to get [tex]\tau[/tex].

Also, this is where my confusion comes in, if after 5 minutes the aluminum bob is oscillating at half its initial amplitude, wouldn't the brass bob be the exact same? Then the answer would be .5A.