Pendulum on the end of a rotating disk

Click For Summary

Homework Help Overview

The discussion revolves around a pendulum attached to a rotating disk, where participants are tasked with calculating the angle of displacement (Φ) of the pendulum based on the angular velocity (ω) of the disk. The problem involves concepts from dynamics and rotational motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to relate centripetal and gravitational forces to derive an expression for Φ. Some participants question the correctness of the equations used and the definitions of variables such as r and R. Others suggest drawing a free body diagram to clarify the forces acting on the pendulum.

Discussion Status

The discussion has evolved with participants providing feedback on the original poster's approach. There is an indication that the original poster has gained some clarity on the problem, and further exploration of the forces involved has been suggested. However, there is no explicit consensus on the final approach or solution.

Contextual Notes

Participants note the importance of distinguishing between the radius of the disk (R) and the distance from the mass to the rotational axis (r). There is also a mention of the need for a correct understanding of the forces acting on the pendulum, including the distinction between centripetal force and gravitational force.

Smouk
Messages
7
Reaction score
1

Homework Statement


There's a pendulum with mass m and longitude L strapped to a disk with radius R that rotates with an angular velocity ω. Calculate the angle that the pendulum is shifted (Φ) depending on ω.

You are given m, L, R, ω, g. Calculate Φ depending on ω.

Little drawing (with my amazing Windows Paint skills):
38185108f3682d1e84b5c45030c0032d.png


Homework Equations


Centripetal Force = mω^2r //Will call it CF from now on
Gravitational Force = mg //Will call it GF from now on
The tension is the resultant from both gravitational (opposite direction) and centripetal forces.

The Attempt at a Solution


Using what we've seen on the 2nd point.
CF = sin(Φ) * L
sin(Φ) = CF/L
Φ = arcsin(mω^2r/L)

Now we have Φ depending on ω but we still have to know what is r exactly so we proceed:
d = sin(Φ) * L
R, r and d form a right triangle so we apply Pythagora´s theorem:
r = sqrt(R^2 + d^2) = sqrt(R^2 + sin^2(Φ) * L^2)

That way we end up with:
Φ = arcsin(mω^2*sqrt(R^2+sin^2(Φ) * L^2) / L)

After doing some calculations you end up with:
sin^2(Φ) - sin^2(Φ) = (mRω^2/L)^2

Which basiclly is:
0 = (mRω^2/L)^2

I just think I'm not understanding this problem or I'm doing something wrong somewhere, I'm not asking for anyone to solve it but just to tell me what I'm doing wrong so I can figure it out.

Thanks to everyone!
 
Physics news on Phys.org
For starters
If by CF you mean "centripetal force"
1. the equation CF = sin(Φ) * L is incorrect.
2. the centripetal force points towards the center of the cicle that the mass describes, not tangent.
3. what is the difference between r and R in you drawing? How is r defined?

On edit: Draw a free body diagram in which the vertical axis of rotation and the string are in the plane of the screen. It will be easier for you to see (and for us to explain) what is going on.
 
kuruman said:
For starters
If by CF you mean "centripetal force"
1. the equation CF = sin(Φ) * L is incorrect.
2. the centripetal force points towards the center of the cicle that the mass describes, not tangent.
3. what is the difference between r and R in you drawing? How is r defined?

On edit: Draw a free body diagram in which the vertical axis of rotation and the string are in the plane of the screen. It will be easier for you to see (and for us to explain) what is going on.
Yeah I just didn't really understand the exercise. I even drew the centripetal force wrong as the pendulum doen't swing like that but outwards, I just ended up figuring it out.

Decomposed both the gravitational force and the inertia (don't really want to say centrifugal force :P) into vectors that are in the same direction of the pendulum's rod and that are also perpendicular to that. We now use those two perpendicular vectors and say they are equal and now we can get from there the angle Φ depending on a given ω.

R was the radius of the disk and r the distance of the mass to the rotational axis (I'm not sure if that's how you say it).

Thank you for trying to help me! :smile:
 
Smouk said:
R was the radius of the disk and r the distance of the mass to the rotational axis (I'm not sure if that's how you say it).
That's a good way to say it. It looks like you were able to finish the problem. Is that right?
 
kuruman said:
That's a good way to say it. It looks like you were able to finish the problem. Is that right?

Yes!
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
Replies
13
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
4K
Replies
5
Views
10K
  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
3K