Period of a rotating mass held by two strings

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SUMMARY

The discussion centers on the physics problem involving a 4.00 kg block attached to a vertical rod by two strings, with the upper string experiencing a tension of 82.0 N. Participants analyze the tension in the lower cord using the equation T1 cosθ - T2 cosθ - mg = 0, where θ is derived from the geometry of the system. Additionally, they explore the formula for tension in circular motion, T = (2πr) / V, and its application in determining the system's revolutions per minute, particularly when the lower cord goes slack.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with circular motion dynamics
  • Knowledge of trigonometric functions and their applications
  • Basic algebra for solving equations
NEXT STEPS
  • Study the relationship between tension and circular motion using the formula T = (2πr) / V
  • Learn about the conditions for tension in multiple string systems
  • Explore the concept of centripetal force and its role in rotating systems
  • Investigate the effects of slack in cords on rotational dynamics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and rotational dynamics, as well as educators seeking to clarify concepts related to tension and circular motion.

limekiwi
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Homework Statement



The 4.00kg block in the figure (Intro 1 figure) is attached to a vertical rod by means of two strings. When the system rotates about the axis of the rod, the strings are extended as shown in the diagram and the tension in the upper string is 82.0 N.

intro1image.jpg


Homework Equations



a) What is the tension in the lower cord?
b) How many revolutions per minute does the system make?
c) Find the number of revolutions per minute at which the lower cord just goes slack.

The Attempt at a Solution



a) I need to focus on the y-component so..
T1 cos[tex]\theta[/tex] - T2 cos[tex]\theta[/tex] - mg = 0
I find [tex]\theta[/tex] by taking the triangle formed by the rod and two strings...
image2.jpg

cos[tex]\theta[/tex] = 1/1.25
With all this info.. I can find T2. Correct?

b) I know the formula for T is T = (2[tex]\pi[/tex]r) / V... or T = 2[tex]\pi[/tex]*[(Lcos[tex]\theta[/tex])/g]^1/2
Do I actually use this formula? I am a bit confused since later I have to find T when the lower cord slacks. Can someone clear this up for me? :smile:
 
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limekiwi said:
a) ... With all this info.. I can find T2. Correct?

Yes, correct.

b) I know the formula for T is T = (2[tex]\pi[/tex]r) / V... or T = 2[tex]\pi[/tex]*[(Lcos[tex]\theta[/tex])/g]^1/2
Do I actually use this formula? I am a bit confused since later I have to find T when the lower cord slacks. Can someone clear this up for me? :smile:

What equation involves force and circular motion?
 

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