1. The problem statement, all variables and given/known data Two identical rollers are mounted with their axes parallel, in a horizontal plane, a distance 2d = 26.5 cm apart. The two rollers are rotating inwardly at the top with the same angular speed (w). A long uniform board is laid across them in a direction perpendicular to their axes. The board of mass m = 3.52 kg is originally placed so that its center of mass lies a distance x(initial) = 10 cm from the point midway between the rollers. The coecient of friction between the board and rollers is k = 0.653. What is the period (s) of the motion? 2. Relevant equations Merg, I'm not sure? x(t) = Acos(ωt+phi) T = 2∏(sq)(l/2μg) 3. The attempt at a solution I did attempt it, based on the advice of my tutor and what he found on this board earlier, however, I got something...not right. Not even close. The real answer is .90. I played around with it a bit, trying to put in the actual normal force of the board and such. I feel like the center of mass and where it starts from is important, but i can't figure out how to incorporate either.