Period of Oscillation of Steel Ball

In summary, the conversation discusses the process of finding the length of a glass tube mounted on a flask using the equation for the period. The equation is T=2\pi(ml/\gammaPA)(1/2) and the mass of the ball is calculated using the volume of a sphere of radius 0.01m x the density. The area of the cross section of the tube is also calculated assuming the ball is fitted. The pressure used in the equation is clarified to be 101 325 Pa. The final length of the tube is found to be 38.2m, which seems long for a flask with a diameter of 2 cm.
  • #1
mmmboh
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I already did the first part, and the equation for the period becomes: T=2[tex]\pi[/tex](ml/[tex]\gamma[/tex]PA)(1/2)

I know 12 litres = 0.012 m3, and the the mass of the ball is the volume of a sphere of radius 0.01m x the density = 0.0318 Kg, for pressure I am not sure whether I am suppose to use 1 atm or 101.3 kPa, that's the least of my problems though. The area of the a cross section of the tube, assuming the ball is fitted, is [tex]\pi[/tex](0.01)2=0.000314m3...So assuming all those are right, now I need the length. I thought that maybe the flask also had the same radius as the ball, and so the length would just be 0.012m3/0.0000314m3=38.2m, but when I plug all there numbers into the equation for period I don't get 1 second or anything close as the answer.

Can someone help please?

Edit: Hm...if I use 101 325 Pa as my pressure it works...can someone confirm if what I've done is right? 38.2 m seems awfully long for a flask.
 
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  • #2
The glass tube is mounted on a flask. The diameter of the tube is 2 cm. The volume of the flask is 12 l. You don't even know the shape of the flask, but its diameter definitely is not 2 cm.

ehild
 

What is the period of oscillation for a steel ball?

The period of oscillation for a steel ball refers to the time it takes for the ball to complete one full back-and-forth motion. It is typically measured in seconds and depends on factors such as the mass, length, and stiffness of the ball.

How is the period of oscillation calculated for a steel ball?

The period of oscillation can be calculated using the equation T = 2π√(m/k), where T is the period, m is the mass of the ball, and k is the spring constant. This equation assumes that the ball is undergoing simple harmonic motion.

What factors affect the period of oscillation for a steel ball?

The period of oscillation for a steel ball can be affected by various factors, including the mass of the ball, the length of the string or spring, and the stiffness of the material. Other factors such as air resistance and friction can also impact the period.

How does the period of oscillation change with different materials?

The period of oscillation for a steel ball will vary depending on the material used. For example, a steel ball will have a different period than a rubber ball or a wooden ball. This is because the stiffness and weight of the material can affect the motion and frequency of oscillation.

What are the practical applications of studying the period of oscillation for a steel ball?

Understanding the period of oscillation for a steel ball is important in fields such as physics and engineering. It can also have practical applications, such as in the design of pendulum clocks and other mechanical devices that rely on the motion of a ball suspended on a string or spring.

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