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mmmboh

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I already did the first part, and the equation for the period becomes: T=2[tex]\pi[/tex](ml/[tex]\gamma[/tex]PA)

^{(1/2)}

I know 12 litres = 0.012 m

^{3}, and the the mass of the ball is the volume of a sphere of radius 0.01m x the density = 0.0318 Kg, for pressure I am not sure whether I am suppose to use 1 atm or 101.3 kPa, that's the least of my problems though. The area of the a cross section of the tube, assuming the ball is fitted, is [tex]\pi[/tex](0.01)

^{2}=0.000314m

^{3}...So assuming all those are right, now I need the length. I thought that maybe the flask also had the same radius as the ball, and so the length would just be 0.012m

^{3}/0.0000314m

^{3}=38.2m, but when I plug all there numbers into the equation for period I don't get 1 second or anything close as the answer.

Can someone help please?

Edit: Hm...if I use 101 325 Pa as my pressure it works...can someone confirm if what I've done is right? 38.2 m seems awfully long for a flask.

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