Period & Radius of Circular Motion: Equations Explained

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SUMMARY

The discussion centers on the mathematical relationships governing the period of circular motion and its dependence on radius and applied force. Key equations include centripetal acceleration, expressed as ac = v2/r, and the velocity equation v = 2πr/T, leading to the derived relationship ac = 4π2r/T2. The conversation also touches on the limitations of these equations when applied to rigid rotators, emphasizing that the treatment of uniform circular motion is only applicable to point particles.

PREREQUISITES
  • Understanding of centripetal acceleration and its formula.
  • Familiarity with the concepts of velocity and period in circular motion.
  • Knowledge of rigid body dynamics, particularly rigid rotators.
  • Basic algebra for manipulating equations related to motion.
NEXT STEPS
  • Study the derivation of the centripetal acceleration formula in detail.
  • Explore the differences between point particles and rigid rotators in circular motion.
  • Investigate the effects of varying applied forces on the period of rotation.
  • Learn about the dynamics of rigid bodies in rotational motion, including torque and angular momentum.
USEFUL FOR

Students and educators in physics, mechanical engineers, and anyone interested in the principles of circular motion and dynamics of rigid bodies.

JohnSimpson
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I'm curious, are there any known equations relating the period of a rotating object to the radius of rotation (presumably while under a constant applied force)

What about any relating the applied force to the period?
 
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there is a centripetal acceleration (the acceleration an object while it is moving in a circle, towards the center of the circle)
a_{c} = \frac{v^2}{r}
the velocity is distance (circumference of the circle) and the time is the period of one rotation
v = \frac{2 \pi r}{T}
then a_[c} = \frac{4 \pi^2 r}{T^2}


multiply acceration by force and taht gives the force period relation
 
stunner5000pt said:
multiply acceration by force and taht gives the force period relation

multiply acceration by mass and taht gives the force period relation.

Good analysis stunner !
 
WELL I am no expert in this field... one can attest to that
 
stunner5000pt said:
there is a centripetal acceleration (the acceleration an object while it is moving in a circle, towards the center of the circle)
a_{c} = \frac{v^2}{r}
the velocity is distance (circumference of the circle) and the time is the period of one rotation
v = \frac{2 \pi r}{T}
then a_[c} = \frac{4 \pi^2 r}{T^2}


multiply acceration by force and taht gives the force period relation
And what about the rigid rotators ?

marlon
 
quasar987 said:
I expected that you'd explain things like "what is a rigid rotator" and "how does the treatement of uniform circular motion made by stunner does not apply to it."
The given treatment only applies to point particles, not massive rotating objects (ie rigid rotators like a spinning sphere or rod)

I'd really like to know who is in your avatar, I assume he is some mathematician or physicist who lived some 235 years ago but I've never seen him before.
:biggrin: Nope, he's not a scientist, he is a far greater genius. You certainly know him.

regards
marlon
 
Mozart I believe.
 
Last edited:

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