Periodicity of Inverse Trigonometric Functions

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SUMMARY

The discussion focuses on finding recurring values for trigonometric functions, specifically the periodicity of inverse trigonometric functions. The key equations provided include x = 30 + 360n and x = 150 + 360n for degrees, as well as π/6 + 2πN and 5π/6 + 2πN for radians. The solution to the problem of determining all angle measures for which the cosine of the angle equals 1/2 is established, with the angles being 60 degrees and 300 degrees, and their periodic extensions. The participant successfully grasps the concept of periodicity in trigonometric functions, confirming their understanding of the equations involved.

PREREQUISITES
  • Understanding of trigonometric functions and their properties
  • Familiarity with radians and degrees conversion
  • Knowledge of periodic functions and integer multiples
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the unit circle and its application to trigonometric functions
  • Learn how to derive general solutions for sine and cosine equations
  • Explore the concept of periodicity in other trigonometric functions
  • Practice solving inverse trigonometric equations in both degrees and radians
USEFUL FOR

Students studying trigonometry, educators teaching trigonometric concepts, and anyone looking to deepen their understanding of the periodic nature of trigonometric functions.

Liger20
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Homework Statement



My problem from before has been more or less resolved, but now I have a new, bigger problem. I need to figure out how to find recuring values for trig functions. I'm having a hard time figuring out how to

1. Get the equations associated with a given value for the trig functions
2. Actually finding all of those values.

This is a problem for me because I can tell that this is a critical concept.


Homework Equations



My book gives me these equations for radians: x=30+360n or x=150+360n
For radians: pi/6+2piN or 5pi/6+2piN. The book goes into little detail as to how to work these equations, and I would very much appreciate it if someone could tell me how to work them.



The Attempt at a Solution



One problem reads: List the solutions in degrees: cos^-1(1/2)= 60 (degrees), 300, 420, 660, 780, 1020, and I have absolutely no idea how they came up with that answer. Like I said before, I would really appreciate it if someone could help me with this, and please tell me if I should clarify any part of what I'm asking.
 
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Think about it the other way around: What are all the angle measures (in degrees) for which the cosine of that angle is 1/2?

There are going to be two angles in each 360 degree full circle, so (in degrees),
.5 = cos(60) = cos(300) = cos(360 + 60) = cos(360 + 300) = cos(720 + 60) = cos(720 + 300) = ...

All of the cosine function arguments are of the form 60 + n*360 or 300 + n*360, where n is an integer. (I have shown them for nonnegative integers n, but the pattern applies also to negative integers.
 
Whoa, that just clicked beautifully. THANK YOU! I'm pretty sure I understand what I'm doing now.
 
Liger20 said:
Whoa, that just clicked beautifully. THANK YOU! I'm pretty sure I understand what I'm doing now.

You're welcome!
 

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