Permutations with Repetition and Repeated Elements

  • Context: Undergrad 
  • Thread starter Thread starter Big-Daddy
  • Start date Start date
  • Tags Tags
    Elements Permutations
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 replies · 2K views
Big-Daddy
Messages
333
Reaction score
1
The theory says that if you have x objects containing a repeats of one element and b repeats of another, Np(without repetition)=x!/(a!b!).

If you have x objects and repetitions are allowed, Np(with repetition)=xx, correct?

Combining these, if we have x objects containing a repeats of one element and b repeats of another, and repetitions are allowed, Np(with repetition)=xx/(a!b!). Is this right?
 
on Phys.org