Perpendicular 3Dimensional Vectors

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SUMMARY

To find a perpendicular vector to two 3-dimensional vectors, the most efficient method is to use the cross product of the two vectors. This technique involves calculating the determinant of the components (i, j, k) of the vectors. An alternative method is to find a vector whose dot product with each of the original vectors equals zero, although this approach is considered more complex and less practical. Both methods ultimately yield the same result, confirming the relationship between the cross product and the normal vector to the plane formed by the two vectors.

PREREQUISITES
  • Understanding of 3D vector mathematics
  • Familiarity with the cross product operation
  • Knowledge of dot product calculations
  • Basic concepts of vector spaces and planes
NEXT STEPS
  • Study the properties and applications of the cross product in vector calculus
  • Learn how to compute the dot product and its geometric interpretations
  • Explore vector projections and their relevance in 3D space
  • Investigate the use of determinants in solving vector-related problems
USEFUL FOR

Students and professionals in mathematics, physics, and engineering who require a solid understanding of vector operations in three-dimensional space.

thursdaytbs
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How would you go about finding a perpendicular vector, to two 3 dimensional vectors? One way, I solved is using the cross product of the two vectors. Splitting the i's j's and k's up and solving using a determinent. But, what's another way to do it?
 
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Find the normal to the plane that contains the two vectors?
 
whozum said:
Find the normal to the plane that contains the two vectors?

That's the same thing.

thursdaytbs said:
But, what's another way to do it?

You did it "the easy way", which is how I would have done it. "The hard way" would be to find a vector whose dot product with each of the first two vectors vanishes. Pure silliness, that route.
 
That's the same thing.

Worded differently, might have given him a different idea? :confused:
 

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