Pf = Pi * (Vi/Vf)^5/3 (since gamma = 5/3 for a monatomic gas)

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SUMMARY

The discussion centers on the calculation of final pressure and temperature for an ideal monatomic gas undergoing adiabatic compression. The initial conditions are 1 atm pressure and a volume of 0.01 m³, which is compressed to 1/8 of its original volume. The final pressure is calculated as 32 atm using the formula pf = pi(Vi/Vf)^(5/3), where gamma equals 5/3 for a monatomic gas. The final temperature is determined to be 487.5 K using the ideal gas law.

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One mole of an ideal monatomic gas, initially at 1 atm pressure, is surrounded by adiabatic walls in a container of volume 0.01 m3 . The gas is compressed until the volume is 1/8 of the original volume. Calculate the final pressure and temperature.

^^ I'm having problems following this question. Its only a short answer, but I'm confused none the less!

A: pV^5/3 = constant.
pf = pi(Vi/Vf )^5/3 = 1(8)^5/3 = 25 = 32 atm.
Tf = pfVf /nR = 32 × (0.01/8)101325/8.314 = 487.5 K

I understand the last line in normal ideal gas equation, but the first two lines, which reference the equation: pV^5/3 = constant has thrown me, i don't know how the second line follows (where does pf=pi*(vi/vf)^5/3 come from? i see its similar to the constant equation
 
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125.6 said:
One mole of an ideal monatomic gas, initially at 1 atm pressure, is surrounded by adiabatic walls in a container of volume 0.01 m3 . The gas is compressed until the volume is 1/8 of the original volume. Calculate the final pressure and temperature.

^^ I'm having problems following this question. Its only a short answer, but I'm confused none the less!

A: pV^5/3 = constant.
pf = pi(Vi/Vf )^5/3 = 1(8)^5/3 = 25 = 32 atm.
Tf = pfVf /nR = 32 × (0.01/8)101325/8.314 = 487.5 K

I understand the last line in normal ideal gas equation, but the first two lines, which reference the equation: pV^5/3 = constant has thrown me, i don't know how the second line follows (where does pf=pi*(vi/vf)^5/3 come from? i see its similar to the constant equation

For adiabatic processes (no heat exchanged withthe surroundings) in ideal gases, P*V^gamma = constant. Gamma is the ratio of the heat capacities at constant pressure and constant volume. For an ideal monatomic gas, C_v = 3/2 * R, and C_p = 5/2* R, so gamma = (5/2 * R) / (3/2 * R) = 5/3.

http://en.wikipedia.org/wiki/Adiabatic_process
 
Quantum Defect said:
For adiabatic processes (no heat exchanged withthe surroundings) in ideal gases, P*V^gamma = constant. Gamma is the ratio of the heat capacities at constant pressure and constant volume. For an ideal monatomic gas, C_v = 3/2 * R, and C_p = 5/2* R, so gamma = (5/2 * R) / (3/2 * R) = 5/3.

http://en.wikipedia.org/wiki/Adiabatic_process

Yeah, thanks

The part i still don't understand is how the equation pf = pi*(vi/vf)^5/3 follow?
 
125.6 said:
Yeah, thanks

The part i still don't understand is how the equation pf = pi*(vi/vf)^5/3 follow?
Pf * Vf^gamma = constant = Pi * Vi^gamma
Pf = Pi * (Vi/Vf)^gamma
 

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