1. The problem statement, all variables and given/known data 175 cm3 of hot tea at 87°C are poured into a very thin paper cup with 80 g of crushed ice at 0°C. Calculate the final temperature of the "ice tea". (Hint: think about two processes: melting the ice into liquid and, maybe, warming the liquid.) 2. Relevant equations Q=mc(deltaT) Q=mL 3. The attempt at a solution First, I calculated the heat loss by the tea: Q1=(.0175)(4186)(87)=63731.9J Then the heat needed to melt the ice: Q2=(0.08)(33.5e4)=26800J Heat gain by the melted ice-water Q3=(.08)(4186)(87)=29134.6J Then Q(final)= Q1-Q2-Q3 =7797.34J Set it equal to the entire system 7797.34J=(0.255)(4186)(T) My answer is 7.3 deg Celsius, which is wrong. I can't seem to find what I did wrong!!! Please help! Thanks.