How Do You Calculate the Final Temperature of Ice Tea Mixing Hot Water and Ice?

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SUMMARY

The final temperature of the ice tea mixture can be calculated using the principle of conservation of energy, specifically the equation 0 = m1c1ΔT1 + m2c2ΔT2. In this scenario, 215 cm³ of hot tea at 95°C is mixed with 40 g of crushed ice at 0°C. The calculation must account for the melting of the ice into water and the subsequent warming of that water. Proper application of these concepts will yield the correct final temperature of the mixture.

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Herbertus
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Homework Statement



215 cm3 of hot tea at 95°C are poured into a very thin paper cup with 40 g of crushed ice at 0°C. Calculate the final temperature of the "ice tea". (Hint: think about two processes: melting the ice into liquid and, maybe, warming the liquid.)

Homework Equations


0 = m1c1ΔT1 + m2c2ΔT2

Q=mc (change in T)

The Attempt at a Solution



I am fairly certain I am doing this correctly, but my homework is online and it is coming back incorrect (for this and another that does not even have latent heat).
I just want to check and see if it is me or the program being useless as always.
 
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Herbertus said:

Homework Statement



215 cm3 of hot tea at 95°C are poured into a very thin paper cup with 40 g of crushed ice at 0°C. Calculate the final temperature of the "ice tea". (Hint: think about two processes: melting the ice into liquid and, maybe, warming the liquid.)

Homework Equations


0 = m1c1ΔT1 + m2c2ΔT2

Q=mc (change in T)

The Attempt at a Solution



I am fairly certain I am doing this correctly, but my homework is online and it is coming back incorrect (for this and another that does not even have latent heat).
I just want to check and see if it is me or the program being useless as always.

Welcome to PF,

Although you haven't really posted an attempt, it seems from the equations that you listed, that you haven't really considered the melting of the ice as the problem suggested.
 

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