Phase Space Factor: Confused About 3D to 4D Conversion

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Discussion Overview

The discussion revolves around the conversion between three-dimensional and four-dimensional differential measures in the context of phase space factors in particle physics. Participants explore the implications of the Lorentz invariant phase space and the role of constraints such as the delta function.

Discussion Character

  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant expresses confusion regarding the equation relating three-dimensional and four-dimensional differential measures in phase space.
  • Another participant clarifies that the equation does not represent a strict equality but rather indicates that the two measures are equivalent under certain assumptions, specifically that the energy is positive and the particle is on-shell.
  • A further contribution highlights the role of the delta function as a constraint that effectively reduces the dimensionality of the integral by one.

Areas of Agreement / Disagreement

Participants appear to reach a mutual understanding regarding the interpretation of the equation, though the initial confusion indicates that the topic may still hold complexities for some.

Contextual Notes

The discussion does not resolve all potential assumptions or implications of the delta function and its role in dimensionality reduction, leaving some aspects open for further exploration.

Josh1079
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Hi,

I'm recently reading "Particle Physics in the LHC Era" and there is a part about the phase space factor that confuses me. When giving the Lorentz invariant phase space, they wrote:

d3p / 2E = θ(E) δ(p2 - m2) d4p

This is very confusing as it equates a three dimensional differential to a four dimensional one. Is there anything I didn't take into account?

Thank you!
 
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Well...actually that equal sign is not really an equal sign. It just means these two are the same integral measures and that's because we're assuming the energy is positive and the particle is on-shell(i.e. satisfies ## p^2=m^2 ##).
So it actually means ## \displaystyle \int f(E,\mathbf p) \frac{d^3\mathbf p}{2E}=\int f(p) \theta(E)\delta(p^2-m^2)d^4p ##, where ##\mathbf p## is a three-vector and ##p## is a four-vector.
 
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Josh1079 said:
Is there anything I didn't take into account?

The delta function, which functions as a constraint that reduces the dimensionality by 1.
 
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Thank you so much ShayanJ! I get it now!

And also thanks to Vanadium 50 for pointing that out!
 

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