Photo-electric effect, Compton Scattering

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Homework Help Overview

The discussion revolves around the photoelectric effect and Compton scattering, specifically focusing on calculating the maximum kinetic energy of electrons ejected from a copper foil by an incident beam of 17.5 KeV rays. The original poster is grappling with the relationship between energy loss and wavelength change in this context.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the energy transferred to an electron during Compton scattering by considering the change in wavelength. They question the validity of their approach when comparing their result to the answer key.
  • Some participants point out the need to differentiate between the original and final energies of the photon, suggesting a misunderstanding in the application of energy equations.

Discussion Status

The discussion is active, with participants exploring the calculations involved in determining the energy transfer during Compton scattering. Some guidance has been provided regarding the correct method to calculate energy differences, but no consensus has been reached on the original poster's approach.

Contextual Notes

Participants are working under the assumption that the work function is negligible and are discussing the implications of this assumption on their calculations. There is also a mention of an answer key that provides a different result, which is influencing the discussion.

mm2424
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Homework Statement


What is the maximum kinetic energy of electrons knocked out of a thin copper foil by Compston scattering of an incident beam of 17.5 KeV rays? Assume the work function is negligible.


Homework Equations


Δλ = h/mc (1-cosθ)


The Attempt at a Solution



I reasoned that the greatest energy transfer to an electron will occur when the x-ray rebounds at 180 degrees, in which case the change in wavelength is 4.85 x 10^-12 m.

I figured that the wavelength of the x-rays increases by this amount, thereby decreasing in energy. I thought I could therefore take this change in wavelength and calculate the energy associated with it using E = hc/Δλ, and I got E = 256 KeV.

However, the answer key requires that you calculate the wavelength of the original x-ray, add Δλ, then calculate the energy and deduct the original energy. It yields a different answer, 1.1 KeV.

I don't understand why you can't say that the energy loss associated with the increase in the wavelength of the x-ray is completely transferred to the electron and then be done with it. What am I missing? Thanks!
 
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Does anybody have any insight into what I'm doing wrong here? I'd appreciate any and all help :).
 
mm2424 said:

The Attempt at a Solution



I reasoned that the greatest energy transfer to an electron will occur when the x-ray rebounds at 180 degrees, in which case the change in wavelength is 4.85 x 10^-12 m.

I figured that the wavelength of the x-rays increases by this amount, thereby decreasing in energy.
So far, so good.
I thought I could therefore take this change in wavelength and calculate the energy associated with it using E = hc/Δλ, and I got E = 256 KeV.
Not quite. First, note that it's impossible for a 17.5 keV photon to lose 256 keV of energy.

You have two energies, E1 = hc/λ1 and E2 = hc/λ2.

The energy difference E1-E2 is the difference between the hc/λ terms, not hc/Δλ. What you did is equivalent to saying
(1/5) - (1/3) = 1/(5-3) = 1/2,​
which is not true.

Can you take it from here?

However, the answer key requires that you calculate the wavelength of the original x-ray, add Δλ, then calculate the energy and deduct the original energy. It yields a different answer, 1.1 KeV.
Yes, that is the basic idea.
 
Thanks, that makes sense!
 

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