Photoelectric Effect and circuits

[Noir]

Homework Statement

When 520nm light falls on a metal, the current through the circuit is brought to zero by a reverse voltage of 1.13V. What is the threshold frequency for this metal.

Homework Equations

E = h.f

The Attempt at a Solution

Using the above formula I get an threshold frequency of 2.72 x 10^14 Hz. Except here's my question, the reverse voltage doesn't have anything to do with the work function if it brings the current down to zero. Or does it, can someone please explain the process? I'm just confused by the term reverse voltage, or stopping voltage.

Thanks for any help :)

 

[rl.bhat]

The maximum kinetic energy of the ejected electron is given by the stopping potential.
According to photoelectric effect
KE = hν - φ where φ is the work function.

 

[Noir]

Thanks for your reply, but I'm still unclear on how the reverse voltage, or stopping voltage relates to the equarion.

 

[rl.bhat]

Kinetic energy = e*V, where e is the charge on electron and V is the stopping voltage.