Photoelectric Effect and the human eye

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Homework Help Overview

The problem involves calculating the number of photons corresponding to a specific energy threshold detectable by the human eye, focusing on the photoelectric effect and the properties of light at a wavelength of 600 nm.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of energy per photon and the total energy detectable by the eye. Questions arise regarding the interpretation of the phrase "under favorable circumstances" and whether it indicates a minimum or maximum energy threshold.

Discussion Status

There is an ongoing exploration of the assumptions behind the problem's wording and the implications for the number of photons detected. Some participants express agreement on the calculations, while others seek clarification on the interpretation of the energy threshold.

Contextual Notes

Participants note that the problem's phrasing may lead to different interpretations regarding the minimum energy detectable by the eye and the implications for photon detection.

daveyman
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Homework Statement


Under favorable circumstances the human eye can detect 1.0e-18 J of electromagnetic energy. How many 600-nm photons does this represent?
(Modern Physics, Arthur Beiser, 6th Edition, Pg. 89)


Homework Equations


My answer is unreasonably low. My mistake is probably very simple, but I'm not sure what it is. Any ideas?


The Attempt at a Solution


First, I attempted to find the energy in a single photon with a wavelength of 600nm.
Since E=hf, I simply multiplied h and f.
I found f by the relationship f=c/lambda.
So, (6.626e-34)(3e8)/(600e-9) = 3.313e-19

Then, I just divided the total amount of energy by this amount (the amount of energy in a single proton).

(1.0e-18)(3.313e-19) = 3.02

I'm guessing that the eye can detect more than 3 photons at a time :-) but I'm not sure what I'm doing wrong. Help!
 
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Yes, the eye can detect more than three photons at a time, but, according to this problem, apparently it can't detect less than 3 photons at a time. You are finding the minimum amount of 600nm photons the eye can detect, by utilizing the minimum energy the eye can detect.

Your work looks fine to me.
 
Thanks for the quick response! I'm glad to hear that my work makes sense, but how did you come to the conclusion that the given energy is a minimum? The way it is worded ("under favorable circumstances") it almost sounds like it would be maximum...
 
I interpreted "under favorable circumstances" as "maximum performance of the eye" i.e. the smallest amount of light the eye can detect will be less and less as it performs better.

So, I interpret the result as:

"Under favorable circumstances, i.e. when your eyes are performing at their very best, they can distinguish at least three photons at a time, but no less.

Also, we know for a fact that the eye can detect more than that amount of energy, so it can't be a maximum.
 
Oh! - the performance of the eye here is based on how little light the eye can still distinguish - I totally get it! That makes tons of sense, actually - thanks!
 
No problem.:smile:
 

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