Photoelectric Effect: Intensity & Frequency Effects

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SUMMARY

The discussion centers on the photoelectric effect, emphasizing that the minimum work function must be met for electron emission. It is established that increasing frequency above the work function leads to constant current, regardless of intensity. The relationship between intensity and current is clarified: higher intensity results in more photons striking the metal, thus increasing the number of emitted electrons. The formula I = q/t is referenced to illustrate this relationship.

PREREQUISITES
  • Understanding of the photoelectric effect
  • Knowledge of work function in physics
  • Familiarity with the relationship between intensity and current
  • Basic grasp of electron emission and photon interactions
NEXT STEPS
  • Research the concept of work function in different materials
  • Explore the mathematical derivation of the photoelectric effect
  • Learn about the role of photon energy in electron emission
  • Investigate experimental setups for measuring photoelectric current
USEFUL FOR

Students of physics, educators teaching the photoelectric effect, and researchers interested in quantum mechanics and electron behavior.

Ukitake Jyuushirou
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hello

from my understanding of the photo electric effect, the minimum workfunction must be met before electrons are emitted prior to that, intensity doesn't play a part. if the frequency is increased to juz above the work function and stays constant there and i increase the intensity shouldn't the current detected be constant and the number of electrons emitted per second is the same?
 
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If the photons hitting the metal have enough energy to emit photons then the bigger the intensity the bigger the current. Cause more intensity means that more photons are hitting the metal. That means that more electrons are emitted: I = q/t
 

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