Photoelectric Effect - Wavelength of a Photon

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SUMMARY

The discussion focuses on calculating the wavelength of a photon that possesses the same momentum as an electron traveling at 1.0 x 106 m/s. The correct wavelength is determined to be 0.73 nm. Key equations utilized include kinetic energy (Ek = (m*v2)/2), the relationship between energy and momentum (p = E/c = hf/c = h/λ), and the photoelectric effect equations. The solution involves calculating the electron's momentum and substituting it into the equation for wavelength.

PREREQUISITES
  • Understanding of kinetic energy calculations
  • Familiarity with the photoelectric effect concepts
  • Knowledge of momentum and its relation to wavelength
  • Proficiency in using Planck's constant (h) and the speed of light (c)
NEXT STEPS
  • Study the derivation of the photoelectric effect equations
  • Learn about the relationship between momentum and wavelength in quantum mechanics
  • Explore advanced applications of Planck's constant in photon calculations
  • Investigate the implications of the photoelectric effect in modern physics
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Students in physics, particularly those studying quantum mechanics and the photoelectric effect, as well as educators looking for practical examples of photon and electron interactions.

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Homework Statement


Calculate the wavelength of a photon having the same momentum as an electron
moving at 1.0  106 m/s.
The answer is supposed to be 0.73 nm.

Homework Equations


Ek = (m*v^2)/2
Ek = hf - W
p = E/c = hf/c = h/\lambda


The Attempt at a Solution


I first found Ek using the kinetic energy formula, using the speed of the electron given in the question and the mass of the electron.
I can't quite figure out where to go next.
 
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This problem has nothing to do with the photoelectric effect. Find the momentum of an electron moving at the speed given, substitute it in p = h/λ, and solve for λ.
 
It is in the photoelectric effect section of the book, though.

Alright, thanks.
 

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