# Phyiscs, finding components with per. line

1. Sep 5, 2011

1. The problem statement, all variables and given/known data

You are given vectors A= 5.1 { i } - 7.0 { j } and vec B= - 3.8 { i } + 7.3{j}. A third vector C lies in the xy-plane. Vector C is perpendicular to vector A and the scalar product of vec C with vec B is 16.0.

Find the x -component and y-component of vector vec C

2. Relevant equations

Not sure, I have no idea how to find components of C with no angles given. I used the Pythagorean theorem for finding the magnitudes of A and B, however, I do not know how/if that even helps.

3. The attempt at a solution

Ok, for an attempt, I found the magnitude of A to be 8.6023 m while the magnitude of B to be 8.2293 m. I have tried to find C, but I have many different answers I keep getting, all around 5.0 meters, but definitely not right. I finally reached an answer of -2.04 m for the x-component, and it was utterly wrong.

I really need help. thanks. If you need me to clear anything up, just ask.

Last edited: Sep 5, 2011
2. Sep 5, 2011

### Staff: Mentor

You'll want to take advantage of the properties of the dot product (scalar product) for this problem. Do you know how to calculate the dot product of two vectors from their components?

In order for two vectors to be perpendicular, what must be the value of their dot product?

3. Sep 5, 2011

Yes, I know that vector A*B = AxBx + AyBy + AzBz, but I don't understand how I'm suppose to find C components by using scalar products.

(-3.81 i)(x)+(7.3 i)(y) = 16.0 meters.

B*C = 16.0 meter(scalar product)

However, how do I find X or Y this way?
Thats where I have issues finding the components of C.

Last edited: Sep 5, 2011
4. Sep 5, 2011

What he was trying to say is the dot product of two perpendicular vectors is 0

5. Sep 5, 2011

Does than mean that the C x-component and y-component are zero?

6. Sep 5, 2011

No A doted with C equals 0 then B doted with C = 16. I'm not positive but I'm sure you could just use a simple linear system to figure it out.

7. Sep 5, 2011

Alright, I see what you mean, but then I just get led back to my original equation of B*C =16.0 with 2 variables, which I don't know how to put two and two together(A*C = 0, B*C=16).

8. Sep 5, 2011

Thats just it have you solved linear systems before? I worked it out it works.
5.1x-7.0y=0
-3.8x+7.3y=16
just solve that.

9. Sep 5, 2011