Physical Meaning and Evaluation of Complex Integral in Heat Conduction Problems

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SUMMARY

The discussion centers on the evaluation and physical interpretation of the integral \(\int\frac{dx}{\cosh^{3n+1}(bx)}\) in the context of heat conduction problems. The expression \(\sqrt{-\sinh^{2}(bx)}\) is analyzed, revealing that it relates to the imaginary components of the hypergeometric function \(_{2}F_{1}\left(\frac{1}{2},-\frac{3n}{2};\frac{2-3n}{2};\cosh^{2}(bx)\right)\), which undergoes analytic continuation. This continuation results in the cancellation of imaginary terms, ensuring the antiderivative remains real. The evaluation at \(x=L\) is crucial for practical applications in heat conduction analysis.

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  • Understanding of hypergeometric functions, specifically \(_{2}F_{1}\)
  • Knowledge of heat conduction principles and mathematical modeling
  • Familiarity with complex analysis and analytic continuation
  • Proficiency in evaluating integrals involving hyperbolic functions
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JulieK
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Hello
In the following integral which I obtained from Wolfram, what is the physical meaning (e.g. in a heat conduction problem) of [tex]\sqrt{-\sinh^{2}(bx)}[/tex]. Also how to evaluate this at [tex]x=L[/tex].
Thanks.

[tex] \int\frac{dx}{\cosh^{3n+1}(bx)}=\frac{\sinh(bx)\cosh^{-3n}(bx)}{3nb\sqrt{-\sinh^{2}(bx)}}\,_{2}F_{1}\left(\frac{1}{2},-\frac{3n}{2};\frac{2-3n}{2};\cosh^{2}(bx)\right)[/tex]
 
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The antiderivative of a real function can not possibly be complex, So perhaps the hypergeometric function has imaginary terms that cancel it out.
 
Last edited:
That is indeed the case as the parameters to the Hypergeometric function force it into it's analytic continuation giving rise to a imaginary number which cancels the i in the denominator.
 

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