How Far Will a Bungee Cord Stretch During a Jump?

Click For Summary
The discussion revolves around calculating the maximum stretch of a bungee cord during a jump, involving a 70.0 kg woman, a 5.00 m cord, and a spring constant of 122.08 N/m. Participants emphasize the importance of energy conservation principles, including gravitational potential energy, kinetic energy, and spring energy in solving the problem. The initial speed upon the cord starting to stretch is calculated, and there is a suggestion to analyze the jump in phases for clarity. The conversation also touches on the need to solve a quadratic equation to determine the maximum extension of the cord. Overall, the thread highlights the complexities of applying physics concepts to bungee jumping scenarios.
coglon
Messages
8
Reaction score
0
I am stumped... very hard question:
"A 70.0kg woman does a bungee jump. The length of the bungee cord is 5.00m and it has a spring constant of 122.08 N/m. Assume the gravitational field strength is 9.81 N/kg.

a)What is the maximun distance the bungee cord will stretch and how far will the jumper be below her initial start point?

b)How much is the total mechanical energy of the system?

c)How far will the bungee cord be stretched when the jumper is moving at her maximun speed? What is this point called? <- I think its called the equilibrium point.

d)What is the maximun speed the jumper will atain."

So as you can see this is a very difficult question. I've taken some stabs at it with no luck. Heres what I've done so far.. but it might be wrong: I found that the initial speed will begin when cord starts to stretch so after 5m of free fall I found Velocity intial would be 9.9m/s then I started my equations:

Total Energy Mechnical (Emt) = Potential Energy Gravity (-ΔEpg) + Kinetic Energy (ΔEk)
Emt= -ΔEpg + ΔEk
Emt -ΔEpg = Eps (Potential spring Energy)
mgh= 1/2kx² height= x+5 where x is the stretch of the bungee cord
mg(x+5)=1/2kx²
√(2mg(x+5))/x= x
as you can see I am going nowhere... what i got lead to a quadratique equation... I don't know if I need to use one or not

Could some one help me solve this question or atleast get me started.

Thanks for help

Cogon,
 
Physics news on Phys.org
I think maybe you should find the speed at the point when the woman as covered 5 meters, using Free Fall, and the probably relate that to when it has covered x distance.

Yes there's Gravitational Potential Energy and Spring Energy, but also kinetic energy.
 
k, some hints:
- draw a scetch of the process and try to distinguish different phases (the phase before he jumps would be the 1st one, for example).
- try Emt = Epg(h) + Ek(h) + Eps(h). Beware of my different sign-convention but you should be able to translate to yours. Ask yourself why all of the three "contributing energies" are only dependant of the height!
- above energy Emt is conserved as it´s the total energy (not 100% sure what "total mechanical energy" is supposed to be but most probably that).

specific hints:
a) What makes that point special? It should be one of the phases I suggested above.
b) assuming it´s really the conserved total energy that´s meant the question is trivial and only depends on where you set x=0. Chose any phase that seems appropriate to you.
c) I really don´t know what your teacher wants to hear there but "maximum velocity" really doesn´t sound like "equilibrium" to me. Equilibrium between what, btw?
d) If you know the point where the maximum velocity is attained then calculating it out is easy.
 
coglon said:
mgh= 1/2kx² height= x+5 where x is the stretch of the bungee cord
mg(x+5)=1/2kx²
√(2mg(x+5))/x= x
as you can see I am going nowhere... what i got lead to a quadratique equation... I don't know if I need to use one or not
Don't give up so easily. You are on the right track. Now solve the quadratic equation to find the maximum extension (x) of the cord.
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

Replies
44
Views
6K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 14 ·
Replies
14
Views
6K
  • · Replies 1 ·
Replies
1
Views
6K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 16 ·
Replies
16
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
8
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
Replies
6
Views
3K